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12x^2+61x+77=0
a = 12; b = 61; c = +77;
Δ = b2-4ac
Δ = 612-4·12·77
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-5}{2*12}=\frac{-66}{24} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+5}{2*12}=\frac{-56}{24} =-2+1/3 $
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